This section reviews situations where graphing, substitution, and elimination will not find a point of intersection when solving the system of equations.

There are two special cases when solving linear systems of equations.

The first case occurs when solving the systems algebraically. The variables are eliminated, and the left side of the equation does not equal the right side of the equation. Then there is no solution, the lines are parallel.

Example: Solve

-2x + 2y = 6
-x + y = -5

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The second case occurs when solving the systems algebraically. The variables and the constants are eliminated, and both sides of the equation equal zero. Then any number can be a solution; the lines are coinciding.

Example: Solve

3x – 4y = 12
-6x + 8y = -24