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Solve the systemSet of equations: 3x-4y=16;x+2y=-3

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Solution:

3x - 4y = 16 becomes y = (16 - 3x)/ -4 or y = -4 + 3/4x Either version can be entered into y1

x + 2y = -3 becomes y = (-3 - x)/2 or y = -3/2 - 1/2x Either version can be entered into y2

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The solution is (2, -2.5)Close Pop Up