Now that you have mastered parameter changes for parabolas in the form y = x2, let's change our focus on sideways parabolas in the form x = y2.

The parameter changes for a sideways parabola will be similar to the ones you have already practiced. We will use the form:

x = a (yk)2 + h

Remember – whenever the equation is in this form, and the y-term is being squared, the graph is a parabola that opens left or right.

interactive exercise investigating changes in parameters of a horizontal parabola. Assistance may be required.

The Effects of a

The Effects of h and k

Now that you have studied those parameter changes, it's important to note a few details.

The equation is generalized as x = a (yk)2 + h. The h-value is still associated with x and with horizontal translations. When hwas positive, the graph shifted left. When h was negative, the graph shifted right.

Likewise, the k-value is still associated with y and vertical translations. When k was positive, the graph shifted up. When k was negative, the graph shifted down. And the a-value still affects the direction the graph opens (positive to the right and negative to the left) and the width of the parabola. As a gets larger and larger, the parabola appears to get skinnier and skinnier.

Check Your Understanding

  1. If you have the equation x + 5 = (y – 9)2, where will the vertex of the parabola be?
  2. Interactive popup. Assistance may be required.

    Check Your Answer

    The vertex will be at the point (–5, 9).Close Pop Up
  3. What is the vertex for the parabola defined as x – 200 = 2 5 (y + 160)2?
  4. Interactive popup. Assistance may be required.

    Check Your Answer

    The vertex will be at the point (200, –160).Close Pop Up
  5. Where will the vertex be for the equation x – 3 = – 1 5 y2? Which way will the graph open? Why? Will it be narrower or wider than the graph of x = y2? Why?
  6. Interactive popup. Assistance may be required.

    Check Your Answer

    This equation is equivalent to x – 3 = – 1 5 (y – 0)2, so the vertex will be at the point(3, 0). And since the a-value is – 1 5 , it will open LEFT and appear wider than the graph of x = y2. Close Pop Up
  7. What is the equation of the parabola that opens left with a = 4 3 and its vertex at the point (15, –12)?
  8. Interactive popup. Assistance may be required.

    Check Your Answer

    The equation will be x – 15 = –4 3 (y – (–12))2, which would simplify to x – 15 = –4 3 (y + 12)2. Notice the a-value is negative since we are told the parabola opens left. Close Pop Up