In this section, you will use concrete models, or algebra tiles, to represent variables and constants. The algebra tiles will make it easier for you to understand the procedures used in completing the square.

explanation of algebra tiles as a concrete model

To begin with, let’s define the algebra tiles that you will use.

key for the algebra tiles representing x, x-squared, and 1

What are the dimensions of the x2 tile, and how do those dimensions compare to the tile used to represent x?

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The x2 tile has a length of x units and a width of x units, which is the same as the length of the x tile.Close Pop Up

Interactive exercise. Assistance may be required. The model below can be used to represent the polynomial x2 + 8x

Let's generalize what you saw with this one example.

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Pause and Reflect

If the vertex form of the polynomial is (x - h)2 + k and the general form of the polynomial is x2 + bx + c, how are the variables h and k related to the variables b and c?

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If b is an odd number, how would using the method of completing the square be different from when b is an even number?

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If b is an even number, then when you divide b in half, you get a whole number. If b is an odd number, then you will have a decimal or mixed number. The procedures used in completing the square would be the same.

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Practice

  1. What number would you need to add to the expression x2 – 8x in order to complete the square?

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    You will need to add the square of 1 over 2 1 2 of the coefficient of the x-term.Close Pop Up

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    16Close Pop Up
  2. Use the method of completing the square to express x2 - 17x in vertex form.

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    You will need to add the square of 1 over 2 1 2 of the coefficient of the x-term and then factor the resulting expression. Be sure to compensate for the added term by subtracting the same value.Close Pop Up

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  3. Use the method of completing the square to express x2 + 20x = 15 in vertex form.

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    You will need to add the square of 1 over 2 1 2 of the coefficient of the x-term and then factor the resulting expression. Be sure to compensate for the added term by adding the same term to both sides of the equation.Close Pop Up

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