graph of parabola opening up with a vertex at (1,-8)

x

y

Critical Attribute

-2

10

-1

0

x-intercept

0

-6

y-intercept

1

-8

Vertex (minimum)

2

-6

Symmetric point

3

0

x-intercept

4

10

To write an equation, you will actually use the coordinates of the points observed from the graph. The points are displayed in the table.

Using the coordinates of the x-intercepts, you can write an equation in factored form with the coefficient of x2 to be found:

Since the zeros (x-intercepts) occur when x = -1 and x = 3,

y = a(x + 1)(x - 3)

Now, substitute the coordinates from one of the other points on the graph, such as (-2, 10):
Note x-values are indicated in red and y-values are indicated in green.

And solve for “a

10 = a( -2 + 1 )( -2 - 3 )

10 = a( -1 )( -5 )

10 = 5a

2 = a

Now, substitute the value for a back into your equation with your variables:

y = 2(x + 1)(x − 3)
y = 2(x2 − 3x + 1x − 3)

Multiply the two binomials together by distribution.

y = 2(x2 −2x − 3)

Combine the x–terms within the parentheses.

y = 2x2 − 4x − 6

Distribute the 2 to all terms and simplify.