This lesson is about using an equation of a quadratic function to find the characteristics of its graph. You will need a graphing calculator for this lesson.
Recall that the standard form of a quadratic equation is y = ax2 + bx + c where a is the coefficient of x2 and b is the coefficient of x and c is a constant.
Steps
Example
Standard form: y = ax2 + bx + c
Example: y = 2x2 − 12x + 14
First find x by using the formula x = negative b divided by 2a -b 2a .
(This tells us to tak\e the opposite of b and divide it by the quantity of 2 times a.)
First find x by using x = twelve divided by the quantity two times two 12 2(2) = 3.
Next substitute the x-value into the original equation to find y.
y = 2(3)2 − 12(3) + 14 = -4
or y = -4
Vertex is (3, -4)
Since the axis of symmetry for a quadratic function is a vertical line that runs through the vertex, then the equation for the axis of symmetry is x = x-coordinate of vertex.
Axis of symmetry: x = 3
Follow the link below to see how to graph a quadratic function whose equation is in standard form.
Now, let’s put all the characteristics together to determine the parts of the parabola.
I'll do this one...
You do this one...
y = - 2x2 + 4x − 5
y = x2 + 4x + 7
Since a < 0, I know the parabola is facing down.
To find the x-coordinate of vertex, I will use
x = negative b divided by 2a -b 2a
x = negative four divided by the quantity two times negative two -4 2(-2) = 1
To find the y-coordinate of vertex, I will substitute 1 in for x in the original equation.
y = - 2(1)2 + 4(1) − 5 = - 3
Vertex: (1, - 3)
Since the x-coordinate of the vertex is 1, I know that the equation for the axis of symmetry is x = 1.
Since c = -5, I know this is the y-intercept.