In the first section, we started with the parent square root function, y = √x. This equation is in algebraic form. Given any square root function in algebraic form, you can represent the same function easily in other forms.
Let's begin with another square root function in algebraic form.
Example 1: Given y = √(3x + 4),
X | Process | Y |
---|---|---|
- four-thirds 4 3 | √3(- four-thirds 4 3 ) + 4 | 0 |
-1 | Interactive button. Assistance may be required. _____________ √3(-1) + 4 | Interactive button. Assistance may be required. _____________ 1 |
0 | Interactive button. Assistance may be required. _____________ √3(0) + 4 | Interactive button. Assistance may be required. _____________ 2 |
4 | Interactive button. Assistance may be required. _____________ √3(4) + 4 | Interactive button. Assistance may be required. _____________ 4 |
To go from algebraic form to graphical form, the same process applies. Knowing what you learned in Algebra II, Module 3, Lesson 3, we can apply your knowledge of transformations to identify the graph's starting point. First we need to get the equation into the form y = a√(x − h) + k.
Follow through the steps below by clicking on the equal signs to reveal each step.
y = √3x + 4
y Interactive button. Assistance may be required. = = √3(x + four-thirds 4 3 )
y Interactive button. Assistance may be required. = = √3 * √x + four-thirds 4 3